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Improved code calculating the font size / centering the text

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Philipp Klaus 2016-12-19 00:33:36 +01:00
parent cb3cc07389
commit 3c26567223
1 changed files with 14 additions and 11 deletions
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25
brother_ql_web.py
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@ -65,7 +65,10 @@ def get_label_context(request):
'label_size': request.query.get('label_size', "62"),
'margin': int(request.query.get('margin', 10)),
'threshold': int(request.query.get('threshold', 70)),
'align': request.query.get('align', 'center'),
}
context['margin_top'] = int(context['font_size']*0.24)
context['margin_bottom'] = int(context['font_size']*0.45)
def get_font_path(font_family, font_style):
try:
@ -99,24 +102,24 @@ def get_label_context(request):
def create_label_im(text, **kwargs):
im_font = ImageFont.truetype(kwargs['font_path'], kwargs['font_size'])
textsize = im_font.getsize(text)
if 'x' in kwargs['label_size']:
# die-cut labels
im = Image.new('L', (20, 20), 'white')
draw = ImageDraw.Draw(im)
linesize = im_font.getsize(text)
textsize = draw.multiline_textsize(text, font=im_font)
if 'x' in kwargs['label_size']: # die-cut labels
height = kwargs['height']
else:
height = max(textsize[1] * (text.count('\n')+1), kwargs['height'])
height = textsize[1] + kwargs['margin_top'] + kwargs['margin_bottom']
im = Image.new('L', (kwargs['width'], height), 'white')
draw = ImageDraw.Draw(im)
textsize = draw.multiline_textsize(text, font=im_font)
if 'x' in kwargs['label_size']:
# die-cut labels
vertical_offset = (height - textsize[1])//2
if 'x' in kwargs['label_size']: # die-cut labels
vertical_offset = (height - textsize[1])//2
vertical_offset += (kwargs['margin_top'] - kwargs['margin_bottom'])//2
else:
vertical_offset = 0
vertical_offset = kwargs['margin_top']
horizontal_offset = max((kwargs['width'] - textsize[0])//2, 0)
if 'ttf' in kwargs['font_path']: vertical_offset -= 10
offset = horizontal_offset, vertical_offset
draw.multiline_text(offset, text, (0), font=im_font, align="center")
draw.multiline_text(offset, text, (0), font=im_font, align=kwargs['align'])
return im
@route('/api/preview/text/<text>')